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int (10x^9+10^xloge10)/(x^10+10^x) dx is...

`int (10x^9+10^xlog_e10)/(x^10+10^x)` dx is equal to :

A

`10^(x) - x^(10) + C`

B

`10^(x) + x^(10) + C`

C

`(10^(x) - x^(10))^(-1) + C`

D

`log (10^(x) + x^(10)) + C`

Text Solution

Verified by Experts

The correct Answer is:
D
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