Home
Class 12
MATHS
Find the equation of the tangent at t = ...

Find the equation of the tangent at `t = pi/4` to the curve: x = sin 3t, y = cos 2t.

Text Solution

Verified by Experts

The correct Answer is:
`2 sqrt(2) x - 3y - 2 = 0`
Promotional Banner

Topper's Solved these Questions

  • SAMPLE QUESTION PAPER-IX

    ACCURATE PUBLICATION|Exercise SECTION-C|7 Videos

  • SAMPLE QUESTION PAPER-IX

    ACCURATE PUBLICATION|Exercise SECTION-D|6 Videos

  • SAMPLE QUESTION PAPER-IX

    ACCURATE PUBLICATION|Exercise SECTION-D|6 Videos

  • SAMPLE QUESTION PAPER-IV

    ACCURATE PUBLICATION|Exercise (SECTION D) |6 Videos

  • SAMPLE QUESTION PAPER-V

    ACCURATE PUBLICATION|Exercise (SECTION-D)|6 Videos

Similar Questions

Explore conceptually related problems

Find the equations of the tangent line to the curve: y = sin x at x = pi/4

Find the equation of the tangent line to the curve x = theta + sin theta, y = 1 + cos theta at theta = pi/4

Find the equations of the tangent and the normal to the curve x = 1 - cos theta, y = theta - sin theta at theta = pi/4

Find the equation of the tangent to the curve y = 2x^(2) + 3 sin x at x = 0.

Find the equation of tangent to the curve given by x = a sin^3 t, y = b cos^3 t at a point where t = pi/2 .

Find the equations of the tangent line to the curve: y = cot^2x - 2 cot x + 2 at x = pi/4

Find the equations of the tangent line to the curve: y = sec^4 x - tan^4 x at x = pi/3

Find the equations of the tangent and normal to the curve given by : x= a sin^3 theta, y = a cos^3theta at a point, where theta = pi/4

Find the equations of the tangent to the following curves at the given point: x = a sin^3 t , y = b cos^3 t at t = pi/4