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Find the equations of the plane through the line of intersection of `vec(r).(2 hat(i) - 3hat(j) + 4 hat(k)) = 1 and vec(r). (hat(i) - hat(j)) + 4 = 0` and perpendicular to the plane `vec(r).(2 hat(i) - hat(j) + hat(k)) + 8 = 0`. Hence find whether the plane thus obtained contains the line x - 1 = 2y - 4 = 3z - 12.

Text Solution

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The correct Answer is:
`2x - y + z + 8 = 0
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