Home
Class 12
CHEMISTRY
A first order reaction takes 40 min for ...

A first order reaction takes 40 min for 30% completion. Calculate `t_(1/2)`.

Text Solution

Verified by Experts

Let a M be the initial concentration .
After 40 minutes , the concentration is ,
` a - 30 a// 100 = 0.70 a `
` k = 2.303// t log [A]//[A]`
` k = 2.303//40 log a//0.7a`
` k = 8.92 xx 10^(-3) min^(-1)`
The half life period,
`t_(1//2) = 0.69//K =0.693 //8.92 xx 10^(-=3) min^(-1) = 77.7 min`
Promotional Banner

Topper's Solved these Questions

  • SOLVED SAMPLE PAPER, MARCH - 2021

    ACCURATE PUBLICATION|Exercise SECTION -D |16 Videos
  • SOLVED SAMPLE PAPER, MARCH - 2021

    ACCURATE PUBLICATION|Exercise SECTION - B |14 Videos
  • SOLUTIONS

    ACCURATE PUBLICATION|Exercise NUMERICAL QUESTIONS (3 MARKS)|31 Videos
  • SOLVED MODEL TEST PAPER-1

    ACCURATE PUBLICATION|Exercise SECTION D|14 Videos

Similar Questions

Explore conceptually related problems

A first order reaction takes 40 minutes for 20% completion. Calculate its half life period.

A first order reaction takes 30 minutes for 50 % completion. Calculate the time required for 90 % completion of the reaction.

A first order reaction takes 69.3 minutes for 50% completion. Calculate time required for 80% completion of the reaction.

A first order reaction takes 69.3 minutes for 50% completion. Calculate the time required for 80% completion of the reaction.

A first order reaction takes 69.3 minutes for 50 % completion. Calculate time required for half change of reaction.

A first order reaction takes 23.1 minutes for 50% conmpletion. Calculate the time required for 75% completion of this reaction (log 2 = 0. 301) , ( log 3 = 0. 4771) ( log 4 = 0.6021)