A sample of ammonia `(NH_(3))` weighs 2.00g. What mass of sulphur dioxide `(SO_(2))` contains the same number of molecules as are in 2.00 g of ammonia ?

Explanation

Molecular mass of `NH_(3)=14+3xx1`
= 14 + 3 = 17 u
`therefore` According to mole-concept,
17g of `NH_(3)` contains = `6.022xx10^(23)` molecules
1g of `NH_(3)` contains = `(6.022xx10^(23))/17`
2g of `NH_(3)` contains = `(6.022xx10^(23))/17xx2`
= `7.08xx10^(22)` molecules
Now `6.022xx10^(23)` molecules of `SO_(2)` have mass = 64g
1 molecule of `SO_(2)` molecule has mass = `64/(6.022xx10^(23))g`
`7.5xx10^(22)` molecules of `SO_(2)` have mass
= `64/(6.022xx10^(23))xx7.08xx10^(22)g`
= 7.5g