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If a, b, c, d, e are in A.P. then the va...

If a, b, c, d, e are in A.P. then the value of a - 4b + 6c - 4d + e is

A

0

B

1

C

2

D

none

Text Solution

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The correct Answer is:
To solve the problem, we need to find the value of \( a - 4b + 6c - 4d + e \) given that \( a, b, c, d, e \) are in Arithmetic Progression (A.P.). ### Step-by-Step Solution: 1. **Understanding A.P.**: Since \( a, b, c, d, e \) are in A.P., we can express them in terms of the first term \( a \) and the common difference \( d \): - \( a = a \) - \( b = a + d \) - \( c = a + 2d \) - \( d = a + 3d \) - \( e = a + 4d \) 2. **Substituting Values**: We substitute the values of \( b, c, d, e \) into the expression \( a - 4b + 6c - 4d + e \): \[ a - 4(a + d) + 6(a + 2d) - 4(a + 3d) + (a + 4d) \] 3. **Expanding the Expression**: Now, we expand the expression: \[ = a - 4a - 4d + 6a + 12d - 4a - 12d + a + 4d \] 4. **Combining Like Terms**: Combine all the terms involving \( a \) and \( d \): - For \( a \): \[ a - 4a + 6a - 4a + a = 0 \] - For \( d \): \[ -4d + 12d - 12d + 4d = 0 \] 5. **Final Result**: Therefore, the entire expression simplifies to: \[ 0 + 0 = 0 \] Thus, the value of \( a - 4b + 6c - 4d + e \) is **0**.
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