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The series of natural numbers is divided...

The series of natural numbers is divided into groups :
1, (2, 3, 4), (5, 6, 7, 8, 9),…… and so on. Then the sum of the numbers in the nth group is

A

`n^(3) - 3n^(2) + 3n - 1`

B

`(2n - 1) (n^(2) - n + 1)`

C

`n^(3) + (n - 1)^(3)`

D

`n^(3) + (n + 1)^(3)`

Text Solution

Verified by Experts

The correct Answer is:
B, C
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