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In a set of four number, the first three...

In a set of four number, the first three are in GP & the last three are in A.P. with common difference 6. If the first number is the same as the fourth, find the four numbers.

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In a set of four numbers,the first three are in GP & the last three are in AP,with common difference 6. If the first number is the same as the fourth,find the four numbers.

In a set of four numbers, the first three are in GP and the last three are in AP with a common difference of 6. If the number is same as the fourth, then find the four numbers.

Knowledge Check

  • In a set of four numbers the first three are in G.P and the llast three are in A.P with commom diffrence 6 if the first number is the same as the fourth find the third number:

    A
    -8
    B
    4
    C
    2
    D
    can't be determined
  • Out of the four numbers a, b, c, d the first three are in A.P. and last three in H.P., then

    A
    bc = ad
    B
    ac = bd
    C
    ab = cd
    D
    none
  • In an ordered set of four numbers, the first 3 are A.P. And the last three are in G.P. Whose common ratio is 7//4. If the product of the first and fourth of these numbers is 49, then the product of the second and third of these is :

    A
    60
    B
    112
    C
    128
    D
    144
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    The first three of four given numbers are in G.P.and their last three are in A.P.with common difference 6. If first and fourth numbers are equal,then the first number is 2 b.4 c.6 d.8

    Given a sequence of 4 numbers,first,three of which are in G.P.and the last three are in A.P. with common difference six.If first and last terms of this sequence are equal,then:

    If a, b, c, d be four numbers of which the first three are in AP and the last three are in HP then prove that ad=bc.

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