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Show that the equation e^(sinx)-e^(-sinx...

Show that the equation `e^(sinx)-e^(-sinx)-4=0` has no real solution.

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Show that the equation e^(sinx)-e^(-sin x)-4=0 has no real solution.

The solution of the equation e^(sin x)-e^(-sin x)-4=0

The equation e^(sinx)-e^(-sinx)-4=0 has (A) non real roots (B) integral roots (C) rational roots (D) real and unequal roots

e^(sinx)sin(e^(x))

The solution of the equation e^(sinx) -e^(-sinx)-4 = 0 is :

The equation e^(sin x)-e^(-sin x)-4=0 has (A) infinite number of real roots (B) no real roots (C) exactly one real root (D) exactly four real roots