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If a, b , c are vectors such that c = a ...

If a, b , c are vectors such that `c = a + b` and a. b = 0 , then

A

`a^(2) + b^(2) + c^(2) = 0`

B

`a^(2) - b^(2) = 0`

C

`a^(2) + b^(2) = c^(2)`

D

`c = a xx b`

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AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the given information about the vectors \( a \), \( b \), and \( c \). We know that: 1. \( c = a + b \) 2. \( a \cdot b = 0 \) We need to find out what can be concluded from these statements. ### Step-by-step Solution: **Step 1: Understanding the Dot Product Condition** Since \( a \cdot b = 0 \), it implies that vectors \( a \) and \( b \) are perpendicular to each other. This is a key property of the dot product: if the dot product of two vectors is zero, then the vectors are orthogonal. **Hint for Step 1:** Recall that the dot product of two vectors is zero if and only if they are perpendicular. --- **Step 2: Expressing \( c \) in Terms of \( a \) and \( b \)** We have the equation \( c = a + b \). To find the magnitude of \( c \), we can square both sides: \[ |c|^2 = |a + b|^2 \] **Hint for Step 2:** Remember that the magnitude of a vector squared can be expressed using the dot product. --- **Step 3: Expanding the Magnitude Squared** Using the property of the dot product, we can expand the right-hand side: \[ |c|^2 = (a + b) \cdot (a + b) = a \cdot a + 2(a \cdot b) + b \cdot b \] **Hint for Step 3:** When expanding, remember to apply the distributive property of the dot product. --- **Step 4: Substituting the Dot Product Values** Since we know \( a \cdot b = 0 \), we can substitute this into our equation: \[ |c|^2 = |a|^2 + 2(0) + |b|^2 = |a|^2 + |b|^2 \] **Hint for Step 4:** Simplify the equation by substituting known values. --- **Step 5: Conclusion** From the above equation, we conclude that: \[ |c|^2 = |a|^2 + |b|^2 \] This is the Pythagorean theorem, which holds true because \( a \) and \( b \) are perpendicular. Therefore, we can say that: \[ |c| = \sqrt{|a|^2 + |b|^2} \] This means that the magnitude of vector \( c \) is equal to the square root of the sum of the squares of the magnitudes of vectors \( a \) and \( b \). **Final Answer:** The correct conclusion is that \( |c|^2 = |a|^2 + |b|^2 \). ---
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ML KHANNA-ADDITION AND MULTIPLICATION OF VECTORS -Problem Set (2) (MULTIPLE CHOICE QUESTIONS)
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