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If a xx (b xx c) + (a.b)b = (4-2beta-sin...

If `a xx (b xx c) + (a.b)b = (4-2beta-sin alpha) b + (beta^(2)-1)c` and (c.c) a = c where b and c are non-collinear, then scalars `alpha = .........beta = ...... `

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The correct Answer is:
`beta = 1, alpha =2npi + pi//2`
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