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sin(cot^(-1)x)=...

`sin(cot^(-1)x)=`

A

`sqrt((1+x^2)`

B

x

C

`(1+x^2)^(-3//2)`

D

`(1+x^2)^(-1//2)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem \( \sin(\cot^{-1} x) \), we can follow these steps: ### Step 1: Understand the Inverse Function The expression \( \cot^{-1} x \) represents an angle \( \theta \) such that \( \cot \theta = x \). This means that: \[ \theta = \cot^{-1} x \] ### Step 2: Use the Cotangent Identity From the definition of cotangent, we have: \[ \cot \theta = \frac{\text{adjacent}}{\text{opposite}} = x \] This implies that we can represent the sides of a right triangle where the adjacent side is \( x \) and the opposite side is \( 1 \). ### Step 3: Find the Hypotenuse Using the Pythagorean theorem, we can find the hypotenuse \( h \): \[ h = \sqrt{x^2 + 1^2} = \sqrt{x^2 + 1} \] ### Step 4: Find the Sine of the Angle Now, we want to find \( \sin \theta \). Recall that: \[ \sin \theta = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{1}{\sqrt{x^2 + 1}} \] ### Step 5: Write the Final Answer Thus, we have: \[ \sin(\cot^{-1} x) = \frac{1}{\sqrt{x^2 + 1}} \] ### Summary of Steps 1. Recognize \( \theta = \cot^{-1} x \). 2. Set up a right triangle with adjacent side \( x \) and opposite side \( 1 \). 3. Calculate the hypotenuse using the Pythagorean theorem. 4. Use the definition of sine to find \( \sin \theta \). 5. Write the final expression.
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ML KHANNA-INVERSE CIRCULAR FUNCTIONS -Self Assessment Test
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