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If y=cos^(-1)(cos10), " then " y=...

If `y=cos^(-1)(cos10), " then " y=`

A

10

B

`4pi-10`

C

`2pi+10`

D

`2pi-10`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem \( y = \cos^{-1}(\cos 10) \), we need to find the value of \( y \) within the defined range of the inverse cosine function. The range of \( \cos^{-1}(x) \) is from \( 0 \) to \( \pi \). ### Step-by-step Solution: 1. **Understanding the Function**: The function \( y = \cos^{-1}(\cos x) \) returns the principal value of the angle \( x \) in the range \( [0, \pi] \). 2. **Finding the Equivalent Angle**: Since \( 10 \) radians is outside the range \( [0, \pi] \), we need to find an equivalent angle that lies within this range. - The angle \( 10 \) radians can be expressed in terms of \( 2\pi \) (approximately \( 6.2832 \) radians). - We can subtract \( 2\pi \) from \( 10 \) to find an equivalent angle: \[ 10 - 2\pi \approx 10 - 6.2832 \approx 3.7168 \text{ radians} \] - Since \( 3.7168 \) is still greater than \( \pi \), we subtract \( 2\pi \) again: \[ 3.7168 - 2\pi \approx 3.7168 - 6.2832 \approx -2.5664 \text{ radians} \] - This angle is negative, so we add \( 2\pi \) again to find a positive equivalent: \[ -2.5664 + 2\pi \approx -2.5664 + 6.2832 \approx 3.7168 \text{ radians} \] 3. **Finding the Correct Angle**: - The angle \( 10 \) radians can be expressed as: \[ 10 = 2\pi + (10 - 2\pi) = 2\pi + 3.7168 \] - Thus, \( \cos(10) = \cos(3.7168) \). 4. **Using the Inverse Cosine**: - Now, we can use the property of the inverse cosine: \[ y = \cos^{-1}(\cos(10)) = \cos^{-1}(\cos(3.7168)) \] - Since \( 3.7168 \) is not in the range \( [0, \pi] \), we need to find the equivalent angle in that range. The equivalent angle is: \[ y = 2\pi - 3.7168 \] 5. **Calculating the Final Value**: - Calculate \( 2\pi - 3.7168 \): \[ y = 6.2832 - 3.7168 \approx 2.5664 \text{ radians} \] ### Conclusion: Thus, the final value of \( y \) is: \[ y \approx 2.5664 \text{ radians} \]
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ML KHANNA-INVERSE CIRCULAR FUNCTIONS -Self Assessment Test
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  7. If sin(sin^(-1)1/5+cos^(-1)x) =1 then x is equal to

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  8. The value of cos^(-1)(-1)-sin^(-1)(1) is- pi b. pi/2 c. (3pi)/2 d. -(3...

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  9. If sin^(-1) sqrt(x^2+2x+1sec^(-1)) sqrt(x^2+2x+1) = pi/2, x ne 0 then ...

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  10. tan^(-1) ""1/3+tan^(-1)""2/9+tan^(-1)"" 4/33 +….oo is equal to

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  11. Find the set of values of parameter a so that the equation (sin^(-1)x)...

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  12. If sin(sin^(-1)1/5+cos^(-1)x) =1 then x is equal to

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  13. The value of cot[cos^(-1)(7/25)] is

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  14. If x takes negative permissible vlaue then sin^(-1)x=

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  15. cot^(-1)9 + cos^(-1)sqrt(41)/4=

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  16. The principal value of "sin"^(-1)("sin""(5pi)/(3)) is

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  17. The solution set of the equation sin^(-1)x=2 tan^(-1)x is

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  18. If sin^(-1)x+sin^(-1)y+sin^(-1)z=(pi)/(2), then the value of x^(2)+y^(...

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  19. cos(tan^(-1)((1)/(3))+tan^(-1)((1)/(2)))=

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  21. If sin^(-1)((2a)/(1+a^2))+sin^(-1)((2b)/(1+b^2))=2tan^(-1)x , then x i...

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