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AD is internal angle bisector of DeltaAB...

AD is internal angle bisector of `DeltaABC " at " angleA` and DE perpendicular to AD which intersects AC at E and meets AB in F, then:

A

`AF=(4bc)/(b+c) sin " A/2`

B

`AD = (2bc)/(b+c) cos " A/2`

C

AE is harmonic mean of b and c

D

`Delta AEF` is an isosceles triangle

Text Solution

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The correct Answer is:
A, B, C, D
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