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The inverse of the function loge x is...

The inverse of the function `log_e` x is

A

`10^x`

B

`10^(-x)`

C

`e^x`

D

`e^(-x)`

Text Solution

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The correct Answer is:
To find the inverse of the function \( f(x) = \log_e x \), we will follow these steps: ### Step 1: Set the function equal to \( y \) We start by letting \( y = \log_e x \). ### Step 2: Rewrite the equation in exponential form To find the inverse, we need to express \( x \) in terms of \( y \). The logarithmic equation \( y = \log_e x \) can be rewritten in its exponential form: \[ x = e^y \] ### Step 3: Define the inverse function Now that we have \( x \) in terms of \( y \), we can express the inverse function. We replace \( y \) with \( x \) to denote the inverse function: \[ f^{-1}(x) = e^x \] ### Step 4: Verify the inverse function To confirm that \( f^{-1}(x) = e^x \) is indeed the inverse of \( f(x) = \log_e x \), we need to check two conditions: 1. \( f(f^{-1}(x)) = x \) 2. \( f^{-1}(f(x)) = x \) **Check 1:** \[ f(f^{-1}(x)) = f(e^x) = \log_e(e^x) = x \] **Check 2:** \[ f^{-1}(f(x)) = f^{-1}(\log_e x) = e^{\log_e x} = x \] Since both conditions hold true, we have verified that the inverse function is correct. ### Final Answer: The inverse of the function \( \log_e x \) is: \[ f^{-1}(x) = e^x \] ---
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