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If means barX,barY of the variates X and...

If means `barX,barY` of the variates X and Y are eah zero and `sigma_(X)^(2)=sigma_(Y)^(2)=1 and r=r_(XY)ne1`, the value of b such that `X+Y and X+bY` are uncorrelated is

A

`b=0`

B

`b=1`

C

`b=-1`

D

none of these

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The correct Answer is:
To solve the problem, we need to find the value of \( b \) such that the variates \( X + Y \) and \( X + bY \) are uncorrelated. We know that the means \( \bar{X} \) and \( \bar{Y} \) are both 0, the variances \( \sigma_X^2 \) and \( \sigma_Y^2 \) are both 1, and the correlation coefficient \( r_{XY} \) is not equal to 1. ### Step-by-Step Solution: 1. **Understanding Uncorrelated Variables**: Two variables are uncorrelated if their covariance is zero. Therefore, we need to find \( b \) such that: \[ \text{Cov}(X + Y, X + bY) = 0 \] 2. **Using the Covariance Formula**: We can use the covariance formula for linear combinations of variables: \[ \text{Cov}(A, B) = \text{Cov}(aX + bY, cX + dY) = ac \text{Var}(X) + bd \text{Var}(Y) + ad \text{Cov}(X, Y) \] For our case, let \( A = X + Y \) and \( B = X + bY \): - Here, \( a = 1, b = 1, c = 1, d = b \). 3. **Calculating Covariance**: Using the covariance formula: \[ \text{Cov}(X + Y, X + bY) = \text{Cov}(X, X) + \text{Cov}(X, bY) + \text{Cov}(Y, X) + \text{Cov}(Y, bY) \] This simplifies to: \[ \text{Cov}(X + Y, X + bY) = \text{Var}(X) + b \text{Cov}(X, Y) + \text{Cov}(Y, X) + b \text{Var}(Y) \] 4. **Substituting Known Values**: Since \( \text{Var}(X) = \text{Var}(Y) = 1 \) and \( \text{Cov}(X, Y) = r_{XY} \): \[ \text{Cov}(X + Y, X + bY) = 1 + b r_{XY} + r_{XY} + b \] This can be rewritten as: \[ \text{Cov}(X + Y, X + bY) = 1 + (b + 1) r_{XY} \] 5. **Setting Covariance to Zero**: For \( X + Y \) and \( X + bY \) to be uncorrelated: \[ 1 + (b + 1) r_{XY} = 0 \] 6. **Solving for \( b \)**: Rearranging gives: \[ (b + 1) r_{XY} = -1 \] Thus, \[ b + 1 = -\frac{1}{r_{XY}} \] Therefore, \[ b = -1 - \frac{1}{r_{XY}} \] 7. **Conclusion**: Since \( r_{XY} \) is not equal to 1, we can conclude that the only value of \( b \) that satisfies the condition for uncorrelation is: \[ b = -1 \] ### Final Answer: The value of \( b \) such that \( X + Y \) and \( X + bY \) are uncorrelated is \( b = -1 \).
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