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If x and y are positive integers and ` ( 3 x )/( y) = 4` then find the minimum value of `( 3 x + 4y) `

A

24

B

1

C

6

D

8

Text Solution

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The correct Answer is:
To solve the problem, we need to find the minimum value of the expression \(3x + 4y\) given the condition \(\frac{3x}{y} = 4\). Let's break this down step by step. ### Step 1: Rearranging the equation From the equation \(\frac{3x}{y} = 4\), we can rearrange it to express \(y\) in terms of \(x\): \[ 3x = 4y \implies y = \frac{3x}{4} \] ### Step 2: Finding integer values for \(y\) Since \(y\) must be a positive integer, \(\frac{3x}{4}\) must also be an integer. This means that \(3x\) must be divisible by \(4\). Therefore, \(x\) must be a multiple of \(4\) because \(3\) and \(4\) are coprime. ### Step 3: Finding the smallest positive integer \(x\) The smallest positive integer \(x\) that satisfies this condition is \(4\) (the smallest multiple of \(4\)): \[ x = 4 \] ### Step 4: Calculating \(y\) Now we can substitute \(x = 4\) back into the equation for \(y\): \[ y = \frac{3(4)}{4} = 3 \] ### Step 5: Calculating the expression \(3x + 4y\) Now that we have both \(x\) and \(y\), we can find the value of the expression \(3x + 4y\): \[ 3x + 4y = 3(4) + 4(3) = 12 + 12 = 24 \] ### Conclusion Thus, the minimum value of \(3x + 4y\) is: \[ \boxed{24} \]
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