Home
Class 12
PHYSICS
A current of 5 A is passing through a no...

A current of 5 A is passing through a non-linear magnesium wire of cross-section `0.04 m^(2)`. At every point the direction of current density is at an angle of `60^(@)` with the unit vector of area of cross-section. The magnitude of electric field at every point of the conductor is :
(Resistivity of magnesium `rho = 44 xx 10^(-8) Omega m`)

A

`11xx10^(-2) V//m`

B

`11xx10^(-7) V//m`

C

`11xx10^(-5) V//m`

D

`11xx10^(-3) V//m`

Text Solution

AI Generated Solution

Promotional Banner

Topper's Solved these Questions

  • JEE MAINS 2021

    JEE MAINS PREVIOUS YEAR|Exercise PHYSICS (SECTION-B)|40 Videos

  • JEE MAINS 2021

    JEE MAINS PREVIOUS YEAR|Exercise PHYSICS (SECTION - A) |40 Videos

  • JEE MAINS 2020

    JEE MAINS PREVIOUS YEAR|Exercise PHYSICS|246 Videos

  • JEE MAINS 2022

    JEE MAINS PREVIOUS YEAR|Exercise PHYSICS (SECTION -B)|10 Videos

Similar Questions

Explore conceptually related problems

A current of 4.8 A is flowing in a copper wire of cross-sectional area 3xx10^(-4) m^(2) . Find the current density in the wire.

A current of 5 A is passing through a metallic wire of cross-section area 4 xx 10^-6 m^2 . If the density of the charge carries in the wire is 5 xx 10^36 //m^3 , the drift velocity of the electrons is.

Calculate the area of cross-section of a wire if its length is .0 m , its resistance is 23 Omega and the resistivity of the material is 1.84 xx 10^-6 Omega m .

A current of 5 ampere is passing through a metallic wire of cross-sectional area 4xx10^(-6) m^(2) . If the density of the charge-carriers in the wire is 5xx10^(26) m^(-3) , find the drift speed of the electrons.

A current of 5A is flowing through magnesium wire.The current density is making an angle of 60^@ with Area vector.Find the electric field.(Given : Area = 2m^2 , rho = Resistivity of Magnesium = 11 ×10^-4 SI units)

What length of a copper wire of cross-sectional area 0.01 mm^2 will be needed to prepare a resistance of 1 kOmega ? Resistivity of copper = 1.7 xx 10^(-8) Omega m .

What length of a copper wire of cross-sectional area 0.01 mm^(2) would be required to obtain a resistance of 1k Omega ? Resistivity of copper =1.7xx10^(-8) Omega m .

62.5 xx 10^(18) electrons per second are flowing through a wire of area of cross-section 0.1m^(2) , the value of current flowing wil be

Calculate the electric field in a copper wire of cross-sectional area 2.0 mm square carrying a current of 2 A. The resistivity of copper is 1.7 xx 10^(-8)Omega m .