A carrier wave `V_(c)(t)=160 sin (2 pi xx 10^(6) t)` volts is made to vary between `V_("max") =200 V and V_("min") =120 V` by a message signal `V_(m) (t)=A_(m) sin (2 pi xx 10^(3) t)` volts. The peak voltage `A_(m)` of the modulating signal is_____.

Equation of messages signal m = 2 sin omega_(m)(t) and carrier signal c = 4 sin omega_(C)(t) . The equation of modulating signal will be

A carrier signal C(t)=25 sin(2.512xx10^(10)t) is amplitude modulated by a message signal m(t)=5 sin(1.57 xx 10^(8)t) and transmitted through an antenna. What will be the bandwidth of the modulated signal ?

Your local radio station relays news signal as V(t)=(20+4sin500 pi t)*cos(2 pi times10^(5)t) Volts.Find the modulation index of the signal.

In amplitude modulation, the message signal V_(m)(t)=10sin(2pixx10^(5)t) volts and Carrier signal V_(C )(t)=20sin(2pixx10^(7)t) volts The modulated signal now contains the message signal with lower side band and upper side band frequency, therefore the bandwidth of modulated signal is alpha KHz. The value of alpha is

In an amplitude modulator circuit the carrier wave is given by C(t) = 4 sin(2 pi × 10^7 t) while modulating signal is given by m(t) = 2 sin(2 pi × 10^5 t) . Then the bandwidth of the broadcast signal will be

A carrier wave of peak voltage 12 V is used to transmit a message signal. What should be the peak voltage of the modulating signal in order to have a modulation index of 75%?

A carrier wave of peak voltage 10 V is used to transmit a message signal. The peak voltage of the modulating signal in order to have a modulation index of 80% is

A carrier wave of peak voltage 12 V is used to transmit a message signal . The peak voltage of the modulating signal in order to have a modulation index of 75 % is

A carrier wave of peak voltage 12 V is used to transmit a message signal. The peak voltage of the modulating signal in order to have a modulation index of 75% is

An alternating voltage is represented by V=80 sin(100 pi t)cos(100 pi t) volt, What is the peak voltage?