Home
Class 12
PHYSICS
A body is projected vertically upward fr...

A body is projected vertically upward from the surface of earth with a velocity sufficient to carry it to initially. Calculate the time taken by it to reach height `h`.

A

`sqrt(R_e/(2g))[(1+h/R_e)^(3//2)-1]`

B

`sqrt((2R_e)/(g))[(1+h/R_e)^(3//2)-1]`

C

`1/3sqrt((R_e)/(2g))[(1+h/R_e)^(3//2)-1]`

D

`1/3sqrt((2R_e)/(g))[(1+h/R_e)^(3//2)-1]`

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • JEE MAINS 2021

    JEE MAINS PREVIOUS YEAR|Exercise PHYSICS (SECTION-B)|40 Videos

  • JEE MAINS 2021

    JEE MAINS PREVIOUS YEAR|Exercise PHYSICS (SECTION - A) |40 Videos

  • JEE MAINS 2020

    JEE MAINS PREVIOUS YEAR|Exercise PHYSICS|246 Videos

  • JEE MAINS 2022

    JEE MAINS PREVIOUS YEAR|Exercise PHYSICS (SECTION -B)|10 Videos

Similar Questions

Explore conceptually related problems

A body is projected vertically upward from the surface of the earth, then the velocity-time graph is:-

A body is projected vertically upward from the surface of the earth with escape velocity. Calculate the time in which it will be at a height (measured from the surface of the arth) 8 time the radius of the earth (R). Acceleration due to gravity on the surface of the earth is g.

A body is projected vertically upwards from the surface of earth with a velocity equal to half the escape velocity. If R be the radius of earth, maximum height attained by the body from the surface of earth is ( R)/(n) . Find the value of n.

An object is projected vertically upward from the surface of the earth of mass M with a velocity such that the maximum height reached is eight times the radius R of the earth. Calculate: (i) the initial speed of projection (ii) the speed at half the maximum height.

A body is projected vertically upwards from the surface of the earth with a velocity equal to half of escape velocity of the earth. If R is radius of the earth, maximum height attained by the body from the surface of the earth is

A body is projected vertically upwards from the surface of a planet of radius R with a velocity equal to hall the escape velocity for that planet. The maximum height attained by the body is

A body is projected vertically up from surface of the earth with a velocity half of escape velocity. The ratio of its maximum height of ascent and radius of earth is

A body is projected vertically upwards from the surface of the earth with an initial velocity v. Show that the it wall go up to a height h given by h=v^(2)R//(2gRv^(2)) and hence deduce the expression for escape velocity .