Home
Class 12
PHYSICS
In the given potentiometer circuit arran...

In the given potentiometer circuit arrangement, the balancing length AC is measured to be 250 cm. When the galvanometer connection is shifted from point (1) to point (2) in the given diagram, the balancing length becomes 400 cm. The ratio of the emf of two cells , `(epsilon_1)/(epsilon_2)` is :

A

`5/3`

B

`8/5`

C

`4/3`

D

`3/2`

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • JEE MAINS 2021

    JEE MAINS PREVIOUS YEAR|Exercise PHYSICS (SECTION-B)|40 Videos

  • JEE MAINS 2021

    JEE MAINS PREVIOUS YEAR|Exercise PHYSICS (SECTION - A) |40 Videos

  • JEE MAINS 2020

    JEE MAINS PREVIOUS YEAR|Exercise PHYSICS|246 Videos

  • JEE MAINS 2022

    JEE MAINS PREVIOUS YEAR|Exercise PHYSICS (SECTION -B)|10 Videos

Similar Questions

Explore conceptually related problems

In a potentiometer experiment , the balancing length for a cell was found to the 1.20 M . Now , a resistance of 10 Omega is connected across the terminals of this cell and the balancing length becomes 80 cm . The internal resistance of this cell is .

In a potentiometer experiment the balancing length is 8 m, when the two cells E_(1) and E_(2) are joined in series. When the two cells are connected in opposition the balancing length is 4m. The ratio of the e.m.f. of two cells (E_(1)//C_(2)) is

In a potentiometer experiment the balancing length with a cell is 560 cm. When an external resistance of 10Omega is connected in parallel to the cell, the balancing length changes by 60 cm. Find the internal resistance of the cell.

In a potentiometer experiment, the balancing length with a cell is 560cm. When an external resistance of 10ohms is connected in parallel to the cell the balancing length changs by 60cm. The internal resistance of the cell in ohm is

In a potentiometer experiment two cells of e.m.f. E and E are used in series and in conjunction and the balancing length is found to be 58 cm of the wire. If the olarity of E is reversed, then the balancing length becomes 29 cm . The ratio (E_(1))/(E_(2)) of the e.m.f. of the two cells is

In a potentiometer experiment the balancing with a cell is at length 240 cm. On shunting the cell with a resistance of 2Omega , the balancing length becomes 120 cm.The internal resistance of the cell is

The balancing length of a potentiometer wire is 220cm when a cell of emf 1.1v is used in the secondary circuit.If it is replaced by a cell of emf 2.5v the balancing length becomes

Two cells of emf E_(1) and E_(2) are to be compared in a potentiometer (E_(1) gt E_(2)) . When the cells are used in series correctly , the balancing length obtained is 400 cm. When they are used in series but E_(2) is connected with reverse polarities, the balancing obtaiend is 200cm. Ratio of emf of cells is