A `16 Omega` wire is bend to form a square loop. A 9 V supply having internal resistance of `1 Omega` is connected across one of its sides. The potential drop across the diagonals of the square loop is `"_______" xx 10^(-1)V`

A 16Omega wire is bend to form a square loop.A 9V battery with internal resistance 1Omega is connected across one of its sides.If a 4 mu F capacitor is connected across one of its diagonals,the energy stored by the capacitor will be (x)/(2)mu J ,where x=

A square loop of total resistance 16 ohm. If a battery of 2V and 1ohm internal resistance is connected across one of its side then find potential difference across its diagnol

A battery of emf 2V and internal resistance 0.5(Omega) is connected across a resistance in 1 second?

A battery has six cells in series. Each has an emf 1.5 V and internal resistance 1 ohm. If an external load of 24Omega is connected to it. The potential drop across the load is

A voltmeter has a resistance of 50 Omega is connected across a cell of e.m.f. 2V and internal resistance 10 Omega . The reading of voltmeter is

The cell has an emf of 2 V and the internal resistance of this cell is 0.1 Omega , it is connected to resistance of 3.9 Omega , the voltage across the cell will be

The cell has an emf of 2 V and the internal resistance of this cell is 0.1 Omega , it is connected to resistance of 3.9 Omega , the voltage across the cell will be