Home
Class 12
PHYSICS
From the given data, the amount of energ...

From the given data, the amount of energy required to break the nucleus of aluminium `""_(13)^(27)` Al is `"_______ "x xx 10^(-3)J.`
Mass of neutron = 1.00866 u
Mass of proton = 1.00726 u
Mass of Aluminium nucleus = 27.18846 u
(Assume 1 u corresponds to x J of energy)
(Round off to the nearest integer)

Promotional Banner

Topper's Solved these Questions

  • JEE MAINS 2021

    JEE MAINS PREVIOUS YEAR|Exercise PHYSICS (SECTION - A) |40 Videos
  • JEE MAINS 2021

    JEE MAINS PREVIOUS YEAR|Exercise PHYSICS (SECTION - B) |20 Videos
  • JEE MAINS 2021

    JEE MAINS PREVIOUS YEAR|Exercise Physics (Section B )|10 Videos
  • JEE MAINS 2020

    JEE MAINS PREVIOUS YEAR|Exercise PHYSICS|246 Videos
  • JEE MAINS 2022

    JEE MAINS PREVIOUS YEAR|Exercise PHYSICS (SECTION -B)|10 Videos

Similar Questions

Explore conceptually related problems

The binding energy per nucleon of ""_(7)N^(14) nucleus is: (Mass of ""_(7)N^(14) = 14.00307 u ) mass of proton = 1.007825 u mass of neutron = 1.008665 u

Given, mass of a neutron =1 .00866u, mass of a proton = 1.00727u, mass of {:(16), (8):}O = 15. 99053u. Then, the energy required to separate {:(16),(8):}O into its constituents is

The energy required to separate the typical middle mass nucleus ._(50)^(120)Sn into its constituent nucleons ( Mass of ._(50)^(120)sn=119.902199u , mass of proton =1.007825 u and mass of neutron =1.008665 u )

Calculate the binding energy for nucleon of . _6^(12) C nucleus, if mass of proton m_p = 10078 u , mass of neutron m_n = 1.0087 u , mass of C_12, m_C =12.0000 u , and 1 u =931 .4 MeV .

What is the binding energy per nucleon of _(6)C^(12) nucleus? Given , mass of C^(12) (m_(c))_(m) = 12.000 u Mass of proton m_(p) = 1.0078 u Mass of neutron m_(n) = 1.0087 u and 1 amu = 931.4 MeV

What would be the energy required to dissociate completely 1 g of Ca-40 into its constituent, particles? Given: Mass of proton =1.00866 am u , Mass of neutron =1.00866 am u , Mass of Ca-40 =39.97454 am u , (Take 1 am u =931 MeV ).

Calculate the binding energy per nucleon of ._(20)^(40)Ca . Given that mass of ._(20)^(40)Ca nucleus = 39.962589 u , mass of proton = 1.007825 u . Mass of Neutron = 1.008665 u and 1 u is equivalent to 931 MeV .

JEE MAINS PREVIOUS YEAR-JEE MAINS 2021-PHYSICS (SECTION-B)
  1. A system consists of two types of gas molecules A and B having same nu...

    Text Solution

    |

  2. A light beam of wavelength 500 nm is incident on a metal having work f...

    Text Solution

    |

  3. A message signal of frequency 20 kHz and peak voltage of 20 volt is us...

    Text Solution

    |

  4. A 16 Omega wire is bend to form a square loop. A 9 V supply having int...

    Text Solution

    |

  5. Two circuits are shown in the figure (a) & (b). At a frequency of rad...

    Text Solution

    |

  6. From the given data, the amount of energy required to break the nucleu...

    Text Solution

    |

  7. A force of F = (5y + 20) hat (j) N N acts on a particle. The workdone ...

    Text Solution

    |

  8. A solid disc of radius 20 cm and mass 10 kg is rotating with an angula...

    Text Solution

    |

  9. In a semiconductor, the number density of intrinsic charge carriers at...

    Text Solution

    |

  10. The nuclear activity of a radioactive element becomes (1/8)^(th) of ...

    Text Solution

    |

  11. Consider an electrical circuit containing a two way switch 'S'. Initi...

    Text Solution

    |

  12. Suppose two planets (spherical in shape) of radii R and 2R, but mass ...

    Text Solution

    |

  13. In Bohr's atomic model, the electron is assumed to revolve in a circul...

    Text Solution

    |

  14. A radioactive sample has an average life of 30 ms and is decaying. A c...

    Text Solution

    |

  15. A particle of mass 9.1 xx 10^(-31) kg travels in a medium with a speed...

    Text Solution

    |

  16. A prism of refractive index n(1) and another prism of refractive index...

    Text Solution

    |

  17. A stone of mass 20 g is projected from a rubber catapult of length 0.1...

    Text Solution

    |

  18. A transistor is connected in common emitter circuit configuration, the...

    Text Solution

    |

  19. The amplitude of upper and lower side bands of A.M. wave where a carri...

    Text Solution

    |

  20. In a uniform magnetic field, the magnetic needle has a magnetic moment...

    Text Solution

    |