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A solution is 0.1 M in Cl^(-) and 0.001...

A solution is 0.1 M in `Cl^(-)` and 0.001 M in `CrO_(4)^(2-)` . Solid `AgNO_(3)` is gradually added to it. Assuming that the addition does not change in volume and `K_(SP) (AgCl) = 1.7 xx 10^(-10) M^(2) and K_(SP)(Ag_(2)CrO_(4)) = 1.9 xx 10^(-12) M^(3)`. Select correct statement from the following:

A

AgCl will preipitate first as the amount of `Ag^(+)` needed to precipitate is low.

B

`Ag_(2)CrO_(4)` precipitates first because the amount of `Ag^(+)` needed is low.

C

AgCl precipitates first because its `K_(SP)` is hight.

D

`Ag_(2)CrO_(4)` precipitates first as its `K_(SP)` is low.

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A solution contains 0.1 M is Cl^(-) and 10^(-4) M CrO_(4)^(2-) . If solid AgNO_(3) is gradually added to this solution, what will be the concentration of Cl^(-) when Ag_(2)CrO_(4) begins to precipitate? (Ksp (AgCl) = 10^(-10) M^(2) , K_(sp) (Ag_(2)CrO_(4)) = 10^(-12)M^(3))

The solubility of AgCl in 0.1 M NaCl is ( K_(sp) of AgCl = 1.2 xx 10^(-10) )

If the solubility of AgCl in 0.1 M NaCl is ( K_(sp) of AgCl = 1.2 xx 10^(-10) )

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Solid AgNO_(3) is gradually added to a solution which is 0.01M n Cl^(-) and 0.01 M in CO_(3)^(2-) K_(sp) AgCl=1.8x10^(-10) and K_(sp)Ag_(2)CO_(3)=4xx10^(-12) The cocentration of Cl^(-) when Ag_(2)CO_(3) starts precipating is

Solid AgNO_(3) is gradually added to a solution which is 0.01M n Cl^(-) and 0.01 M in CO_(3)^(2-) K_(sp) AgCl=1.8xx10^(-10) and K_(sp)Ag_(2)CO_(3)=4xx10^(-12) The minimum concentration of Ag^(+) required to start the precipation of Ag_(2)CO_(3) is

The precipitate of Ag_(2)CrO_(4)(K_("sp") = 1.9 xx 10^(-12)) is obtained when equal volumes of the following are mixed.

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