The product obtained from the electrolytic oxidation of acidified sulphate solutions , is :

Options

A. `HSO_(4)^(-)`
B. `HO_(3)SOOSO_(3)H`
C. `HO_(2)SOSO_(2)H`
D. `HO_(3)SOSO_(3)H`

Answer

To solve the problem of identifying the product obtained from the electrolytic oxidation of acidified sulfate solutions, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Electrolytic Process**:
- When we electrolyze an acidified sulfate solution, we are essentially breaking down the sulfate ions (SO₄²⁻) in the presence of an acid (usually sulfuric acid, H₂SO₄).

2. **Identifying the Reaction**:
- The electrolytic oxidation of sulfate ions leads to the formation of peroxodisulfate (also known as disulfuric acid or oleum). The chemical formula for peroxodisulfate is H₂S₂O₈.

3. **Writing the Reaction**:
- The reaction can be represented as:
\[ 2 \text{SO}_4^{2-} + 2 \text{H}^+ \rightarrow \text{H}_2\text{S}_2\text{O}_8 + \text{H}_2\text{O} \]

4. **Hydrolysis of Peroxodisulfate**:
- If we further hydrolyze H₂S₂O₈, we can break it down into its components:
\[ \text{H}_2\text{S}_2\text{O}_8 + \text{H}_2\text{O} \rightarrow 2 \text{HSO}_4^{-} + 2 \text{H}^+ + \text{H}_2\text{O}_2 \]
- However, the question specifically asks for the product of the electrolytic oxidation, which is H₂S₂O₈.

5. **Conclusion**:
- Thus, the product obtained from the electrolytic oxidation of acidified sulfate solution is H₂S₂O₈ (peroxodisulfate).

### Final Answer:
The product obtained from the electrolytic oxidation of acidified sulfate solutions is **H₂S₂O₈**.