The number of geometrical isomers found in the metal complexes `[PtCl_(2)(NH_(3))_(2)], [Ni(CO)_(4)], [Ru(H_(2)O)_(3)Cl_(3)]` and `[CoCl_(2)(NH_(3))_(4)]^(+)` respectively, are :

Options

A. 1, 1, 1, 1
B. 2, 1, 2, 2
C. 2, 0, 2, 2
D. 2, 1, 2, 1

Answer

To determine the number of geometrical isomers for the given metal complexes, we will analyze each complex one by one.

### Step 1: Analyze the complex `[PtCl2(NH3)2]`
- **Geometry**: This complex is square planar.
- **Ligands**: There are 2 chloride (Cl) ligands and 2 ammonia (NH3) ligands.
- **Geometrical Isomers**:
- **Cis Isomer**: Both Cl ligands are on one side and both NH3 ligands are on the opposite side.
- **Trans Isomer**: One Cl ligand is opposite to the other Cl ligand, and one NH3 ligand is opposite to the other NH3 ligand.

Thus, there are **2 geometrical isomers** for this complex.

### Step 2: Analyze the complex `[Ni(CO)4]`
- **Geometry**: This complex is tetrahedral.
- **Ligands**: All 4 ligands are carbon monoxide (CO), which are identical.
- **Geometrical Isomers**: Since all ligands are the same, there can be no geometrical isomers.

Thus, there are **0 geometrical isomers** for this complex.

### Step 3: Analyze the complex `[Ru(H2O)3Cl3]`
- **Geometry**: This complex is octahedral.
- **Ligands**: There are 3 water (H2O) ligands and 3 chloride (Cl) ligands.
- **Geometrical Isomers**:
- **Facial (fac) Isomer**: All three Cl ligands are on one face of the octahedron.
- **Meridional (mer) Isomer**: The Cl ligands are arranged in a plane that divides the octahedron into two equal halves.

Thus, there are **2 geometrical isomers** for this complex.

### Step 4: Analyze the complex `[CoCl2(NH3)4]^+`
- **Geometry**: This complex is octahedral.
- **Ligands**: There are 4 ammonia (NH3) ligands and 2 chloride (Cl) ligands.
- **Geometrical Isomers**:
- **Cis Isomer**: Both Cl ligands are adjacent to each other.
- **Trans Isomer**: The Cl ligands are opposite each other.

Thus, there are **2 geometrical isomers** for this complex.

### Summary of Results
- For `[PtCl2(NH3)2]`: 2 geometrical isomers
- For `[Ni(CO)4]`: 0 geometrical isomers
- For `[Ru(H2O)3Cl3]`: 2 geometrical isomers
- For `[CoCl2(NH3)4]^+`: 2 geometrical isomers

### Final Answer
The number of geometrical isomers found in the complexes are: **2, 0, 2, 2** respectively.

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