The shapes of `BF_3` and `[BH_4^(-)]` are respectively
A
planar, tetrahedral
B
tetrahedral, planar
C
planar, planar
D
tetrahedral, tetrahedral
Text Solution
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The correct Answer is:
D
In` BF_3` boron is `sp^3`- hybridised as it contains three bond pairs and, therefore, `BF_3` molecule is trigonal planar in shape. On the other hand, in`[BH_4]^(-)` boron is `sp^3`- hybridised because of the presence of four bond pairs and hence, `[BH_4]^(-)` species is tetrahedral in shape.