When excess of NaOH solution is added in potash alumn the product is:
A
Abluish precipitate
B
Clear solution
C
White precipitate
D
Greenish precipitate
Text Solution
Verified by Experts
The correct Answer is:
B
Potash alum is `K_2SO_4 . Al_2 (SO_4)_3 . 24 H_2O` `Al_2(SO_4)_3` reacts with NaOH to form `NaAlO_2` which is soluble `K_2SO_4 and Na_2SO_4` are also soluble and thus a clear solution is obtained in water. `Al_2(SO_4)_3 + 6NaOH to 2Al(OH)_3 + 3Na_2SO_4` `Al(OH)_3 + NaOH to underset("Soluble")(NaAlO_2) + 2H_2O`
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