The formula of a hydrated salt of barium is `BaCl _(2) , x H _(2) O `If 1.936 g of this compound gives 1.846 g of anhydrous `BaSO_(4)` on treatment with `H_(2) SO_(4),` the value of 'x' is:

Answer

2

Explanation

Moles of `Ba SO _(4) = ( 1. 846)/(233) ` (Ba in both): Moles of `Ba Cl _(2) x H _(2) O = ( 1. 936)/(( 137 + 71 + 18 x))`
`therefore ( 1. 9 36)/(137 + 71 + 18 x) = ( 1. 846)/(233) , therefore x =2`