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When CH(2)=CH-COOH is reduced with LiAlH...

When `CH_(2)=CH-COOH` is reduced with `LiAlH_(4)` the compound obtained will be

A

`CH_(3)-CH_(2)-CHO`

B

`CH_(3)-CH_(2)-COOH`

C

`CH_(2)=CH-CH_(2)OH`

D

`CH_(3)-CH_(2)-COOH`

Text Solution

Verified by Experts

The correct Answer is:
C
`LiAlH_(4)` reduces only the-COOH without reducing the double bond
`CH_(2)=CH-COOH overset(LiAlH_(4))to CH_(2) =CH-CH_(2)OH`
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