For the reaction :
`2N_2O_5 rarr 4NO_2+O_2`
the rate of reaction measured as `(Delta[NO_2])/(Deltat)` was found to be `4 xx 10^(-3)" mol L"^(-1)` is `s^(-1)`. Calculate the rate of reaction, expressed in terms of `N_2O_5`

Explanation

`2N_2O_5 rarr 4NO_2+O_2`
Average Rate=`1/2(Delta[N_2O_5])/(Deltat)`
`=1/4(Delta[NO_2])/(Deltat)`
`=(Delta[O_2])/(Deltat)`
`(Delta[O_2])/(Deltat)=4xx10^(-3)" mol L"^(-1)s^(-1)`
`-(Delta[N_2O_5])/(Deltat)=?`
`-(Delta[N_2O_5])/(Deltat)2/4(Delta[NO_2])/(Deltat)=1/2(Delta[O_2])/(Deltat)`
`=1/2xx4xx10^(-3)" mol L"^(-1)s^(-1)`
`=2xx10^(-3)" mol L"^(-1)s^(-1)`