For the reaction :` N _(2) + 3H_(2) to 2 NH _(3)` The rate of reaction measured as `(Delta [ NH _(3) ] )/( Delta t )` we found to be ` 2 xx 10 ^(-4) mol L ^(-1) sec ^(-1).` Calculate the rate of reaction expressed in terms of `N _(2).`

Explanation

Rate=k[A]
When k=0.50 `s^(-1)`
`therefore" Rate"=0.50 s^(-1)[A]`
(a) Rate=?[A]=0.60" mol L"^(-1)
Rate=`0.50s^(-1)xx0.60" mol L"^(-1)`
`=0.03" mol L"^(-1)s^(-1)`
(b) Rate=`2.4xx10^(-2),[A]=?`
[A]=`("Rate")/(k)=(2.4xx10^(-2))/(0.50s^(-1))" mol L"^(-1)s^(-1)`
`=4.8xx10^(-2)" mol L"^(-1)s^(-1)`