For a chemical reaction `X rarr Y`, the rate. increases by a factor 2.25 when the concentration of X is increased by 1.5. What is the order of reaction ?

Explanation

Let rate law expression is ,
rate=k` [conc.]^n`
r=k `[X]^n`
Here `(r_2)/(r_1)=2.25`
and `([X]_2)/([X]_1)=1.5`
`(r_2)/(r_1)=[([X]_2)/([X]_1)]^n`
2.25=`[1.5]^n`
`therefore n=2[because(1.5)^2=2.25]`
`therefore` Order of reaction, n=2