Rate constant for a first order reaction is `60 s ^(-1) . ` How much time will it take to reduce the concentration of the reaction on `(1)/(10)` th of its initial value.

Explanation

`k=60s^(-1),[R]_0=100` (say)
`[R]=(1)/(10)xx100=10`
t=?
`t=(2.303)/(k)log([R]_0)/([R])`
`=(2.303)/(60^(-1))s=3.8xx10^(-2)s`