Calculate two-third life of a first order reaction having
`k=5.48xx10^(-14)s^(-1)`

Explanation

`k=5.48xx10^(-14)s^(-1)`
`[R]_0=100(say),[R]=overset("slow")(rarr)100`
`=(100)/(3)`
t=?
`t=(2.303)/(k)log([R]_0)/([R])`
`=(2.303)/(5.48xx10^(-14)s^(-1))og(100)/(100//3)`
`=(2.303xxlog3)/(5.48xx10^(-14)s^(-1))=(2.303xx0.4771)/(5.48xx10^(-14))`
`=2.005xx10^(13)s`