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A particle carrying a charge 8 muC is m...

A particle carrying a charge `8 muC ` is moving with velocity `vecv = (2hatj -3hatk)ms^(-1)`
in a magnetic field `vecB = (2hatj -3hatk) wbm^(-2)`
Find the force acting on the particle.

Text Solution

Verified by Experts

`q= 8muC = 8 xx 10^(-6)C`
`vecv = (2hatj - 3hatk) ms^(-1)`
`vecB = (2hatj - 3hatk) ms^(-1)`
`vecF = ?`
`vecF = q(vecv xx vecB)`
`rArr vecF = q[(2hatj-3hatk) xx (2hatj xx 3hatk)]`
`rArr vecF = q(0)`
`rArr [because vecv and vecB` are the same vector ]
`rArr F = 0`
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