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A proton enters into a magnetic field or...

A proton enters into a magnetic field or intensity `5 xx 10^(-2) T` with velocity `10^(5)`m/s at an angle of `30^(@)` with the field. Calculate the mangitude of force acting on the proton due to this field.

Text Solution

Verified by Experts

`q = + e = + 1*6 xx 10^(-19)C`
`B = 5 xx 10^(-2)T`
`theta = 30^(@)`
`F = ?`
`F = Bqv sin theta`
` = 5 xx 10^(-2) xx 1*6 xx 10^(-19) xx 10^(5) xx sin 30^(@)`
`F - 8 xx 10^(-16) xx (1)/(2) = 4 xx 10^(-16)N`
`F = 4*0 xx 10^(-16)` N
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