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An electron eneters a magnetic field of ...

An electron eneters a magnetic field of 5 T intensity with velocity of `5xx10^6ms^-1` at an angle of `30^@` with the field. Find the magnitude of the force acting on the electron.

Text Solution

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`q = e = 1*6 xx 10^(-19)C`
`B = 4 xx 10^(-3)T`
`v = 5 xx 10^(5) ms^(-1)`
`F = ?`
`theta = 30^(@)`
`v = 10^(5)ms^(-1)`
`F = Bqv sin 30^(@)`
`F = 4 xx 10^(-3) xx 1*6 xx 10^(-19) xx 5 xx 10^(5) xx sin 30^(@)`
` = 32 xx 10^(-17) xx (1)/(2)`
` F = 1*6 xx 10^(-16) N`
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