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A particle carrying a charge 3*2 xx 10^(...

A particle carrying a charge `3*2 xx 10^(-19)`C enters into a magnetic field of intensity `sqrt(2) xx 10^(-2)T` with velocity `10^(5) ms^(-1)` at an angle `45^(@)` with the field. Calculate the magnitude of force acting on the particle due to the field.

Text Solution

Verified by Experts

`q = 3*2 xx 10^(-19)C`
`B = sqrt(2) xx 10^(-2)T`
`v = 10^(5)ms^(-1)`
`theta = 45^(@)`
`F = ?`
`F = Bqv sin theta`
`F = sqrt(2) xx 10^(-2) xx 3*2 xx 10^(-19) xx 10^(5) xx sin 45^(@)`
` = 3*2 xx sqrt(2) xx 10^(-16) xx (1)/(sqrt(2))`
`F = 3*2 xx 10^(-16)N`
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