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A galvanometer coil has a resistance of ...

A galvanometer coil has a resistance of `15Omega` and the metre shows full scale deflection for a current of 4mA. How will you convert the metre into an ammmeter of range 0 to 6 A?

Text Solution

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Resistance of the galvanometer ` = G = 15 Omega`
`I_(G) = 4mA = 0*004 A = 4 xx 10^(-3)A`
`I = 6A`
Shunt ` = S = ?`
`S = (I_(G))/(I-I_(G))G`
`S = (4xx10^(-13) xx 15)/(6-0*004)`
`S = (60 xx 10^(-3))/(5*996)`
`S = 1 xx 10^(-2)Omega`
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