The IUPAC name of any organic compound consists of four parts, i.e., word root, primary and secondary suffixes and prefixes. The word root denotes the total number of carbon atoms in the longest continuous chain of carbon atoms present in the molecule. The primary suffix denotes whether the compound is saturated (i.e., ane) or unsaturated (i.e., ene or yne) while the secondary suffix denotes the functional group present in the molecule. The primary prefix cyclo is used only when the compound is cyclic in nature while the secondary prefixes denote the substituents and secondary functional groups, if any.
The IUPAC name of the compound
`CH_(3)-CH_(2)-CH_(2)-CH_(2)-OH` is

Options

A. butanol
B. butanal
C. butene
D. propanol

Answer

To determine the IUPAC name of the compound `CH3-CH2-CH2-CH2-OH`, we will follow the systematic approach outlined in the question. Here are the steps to arrive at the correct IUPAC name:

### Step 1: Identify the longest continuous carbon chain
The first step is to identify the longest continuous chain of carbon atoms in the molecule. In this case, we have:

- `CH3-CH2-CH2-CH2`

This chain consists of 4 carbon atoms.

### Step 2: Determine the word root
The word root corresponds to the number of carbon atoms in the longest chain. For 4 carbon atoms, the word root is "but".

### Step 3: Identify the functional group
Next, we need to identify the functional group present in the compound. The `-OH` group indicates that this is an alcohol.

### Step 4: Determine the primary suffix
Since the compound is saturated (it contains single bonds only), we will use the primary suffix "ane". However, because we have a functional group (the alcohol), we will modify this suffix.

### Step 5: Assign the secondary suffix
For alcohols, the secondary suffix is "ol". Since there is only one functional group present, we will drop the "e" from "butane" and add "ol" to get "butanol".

### Step 6: Number the carbon chain
We need to number the carbon chain to give the alcohol group the lowest possible number. Starting from the end closest to the `-OH` group, we number the carbon atoms:

1. C1 - CH3
2. C2 - CH2
3. C3 - CH2
4. C4 - CH2-OH

The `-OH` group is on carbon 1.

### Step 7: Combine the parts to form the IUPAC name
Now we can combine all parts to form the complete IUPAC name. Since the `-OH` group is on carbon 1, we can write the name as:

**Butan-1-ol**

Alternatively, since the position of the functional group is clear, we can also simply refer to it as **Butanol**.

### Final Answer
The IUPAC name of the compound `CH3-CH2-CH2-CH2-OH` is **Butan-1-ol**.

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