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Given that natural sample of iron has is...

Given that natural sample of iron has isotopes `""_(26)^(54) Fe, ""_(26)^(56)Fe` and `""_(26)^(57) Fe` in the ratio of 5%, 90% and 5% respectively . What will be the average atomic mass of iron ?

Text Solution

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Average atomic mass `= ( 54 xx 5 + 56 xx 90 + 57 xx 5)/( 100)`
`= (270+5040+285)/( 100) = 55.95u`
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