A silver ornament of mass 'm' gram is polished with gold equivalent to `1%` of the mass of silver. Compute the ratio of the number of atoms of gold and silver in the ornament. [At. Mass `:` silver = 108u, gold = 197u]

Explanation

Mass of silver = m g
Mass of gold `= ( m )/( 100)`g
Number of atoms of silver `= ( "Mass")/( "Atomic mass") xx N_(A) = ( m )/( 108) xx N_(A)`
Number of atoms of gold `= ( m )/( 100 xx 197) xx N_(A)`
Ratio of number of atoms of gold to silver `= A u : Ag`
`= ( m)/( 100 xx 197) xx N_(A) : ( m )/( 108) xx N_(A)`
`= 108 : 100 xx 197 = 108 : 19700 = 1: 182.41`