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The atomic mass of the lead is 208u and ...

The atomic mass of the lead is 208u and its atomic number is 82, the atomic mass of bismuth is 209u and its atomic number is 83. The ratio of the neutrons `//` protons

A

is higher is lead than bismuth

B

is lower in lead than bismuth

C

is equal in both lead and bimuth

D

does not depend on the above data.

Text Solution

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The correct Answer is:
To find the ratio of neutrons to protons for lead and bismuth, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Atomic Mass and Atomic Number**: - For Lead (Pb): - Atomic mass = 208 u - Atomic number = 82 - For Bismuth (Bi): - Atomic mass = 209 u - Atomic number = 83 2. **Calculate the Number of Neutrons**: - The number of neutrons can be calculated using the formula: \[ \text{Number of Neutrons} = \text{Atomic Mass} - \text{Atomic Number} \] - For Lead: \[ \text{Neutrons in Lead} = 208 - 82 = 126 \] - For Bismuth: \[ \text{Neutrons in Bismuth} = 209 - 83 = 126 \] 3. **Identify the Number of Protons**: - The number of protons is equal to the atomic number. - For Lead: \[ \text{Protons in Lead} = 82 \] - For Bismuth: \[ \text{Protons in Bismuth} = 83 \] 4. **Calculate the Neutron to Proton Ratio**: - For Lead: \[ \text{Neutron to Proton Ratio for Lead} = \frac{126}{82} \] - For Bismuth: \[ \text{Neutron to Proton Ratio for Bismuth} = \frac{126}{83} \] 5. **Compare the Ratios**: - Since both elements have the same number of neutrons (126), but different numbers of protons (82 for Lead and 83 for Bismuth), we can conclude: - The ratio for Lead will be greater than that for Bismuth because the denominator (number of protons) is smaller for Lead. 6. **Conclusion**: - The Neutron to Proton Ratio is higher in Lead than in Bismuth. ### Final Answer: The ratio of neutrons to protons is higher in Lead than in Bismuth. ---

To find the ratio of neutrons to protons for lead and bismuth, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Atomic Mass and Atomic Number**: - For Lead (Pb): - Atomic mass = 208 u - Atomic number = 82 ...
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