The weight of a molecule of the compound`C_(60)H_(122)` is

Options

A. `1.4 xx 10^(-21) g`
B. `1.09 xx 10^(-21) g`
C. `5.025 xx 10^(23) g`
D. `16.023 xx 10^(23) g`

Answer

A

Explanation

Molecular weight of `C_(60) H_(122) = 842 g // "mol"`
`:. 6.022 xx 10^(23)` molecule of `C_(60) H_(122) ` has mass = 842 `g//` mol
`:.` 1 molecule of `C_(60) H_(122)` has mass ` = ( 842)/( 6.022 xx 10^(23))`
`= 1.4 xx 10^(-21)g`