Beakers A, B and C contain zinc sulphate, silver nitrate and iron (II) sulphate solutions respectively. Copper pieces are added to each beaker. Blue colour will appear in case of

Options

A. beaker A
B. beaker B
C. beaker C
D. all the beakers.

Explanation

To determine in which beaker a blue color will appear when copper pieces are added, we need to analyze the reactions that occur in each beaker containing different metal salt solutions.

### Step-by-Step Solution:

1. **Identify the Solutions in Each Beaker:**
- Beaker A: Zinc sulfate (ZnSO₄)
- Beaker B: Silver nitrate (AgNO₃)
- Beaker C: Iron (II) sulfate (FeSO₄)

2. **Understand the Reactivity Series:**
- The reactivity series ranks metals based on their ability to displace other metals from solutions. In this case, copper (Cu) is less reactive than zinc (Zn) and iron (Fe) but more reactive than silver (Ag).

3. **Analyze Beaker A (Zinc Sulfate):**
- When copper is added to zinc sulfate, no reaction occurs because copper cannot displace zinc from its sulfate solution. Therefore, the solution remains colorless.

4. **Analyze Beaker B (Silver Nitrate):**
- When copper is added to silver nitrate, a reaction occurs where copper displaces silver from the solution. The reaction can be represented as:
\[ 2AgNO₃ + Cu \rightarrow 2Ag + Cu(NO₃)₂ \]
- The formation of copper(II) nitrate (Cu(NO₃)₂) results in a blue solution because copper(II) ions (Cu²⁺) impart a blue color to the solution.

5. **Analyze Beaker C (Iron (II) Sulfate):**
- When copper is added to iron (II) sulfate, no reaction occurs because copper cannot displace iron from its sulfate solution. Therefore, the solution remains colorless.

6. **Conclusion:**
- The blue color will appear in **Beaker B**, which contains silver nitrate.

### Final Answer:
The blue color will appear in **Beaker B** (Silver Nitrate).