`{:("LIst-I ",,"LIst-II "),("(P) 2, 8, 1",,"1. Neon"),("(Q) 2, 8, 7",,"2.Sulphur"),("(R) 2,8,6",,"3. Chlorine"),("(S) 2,8",,"4. Sodium"):}`

Options

A. P-4, Q-3, R-2, S-1
B. P-4, Q-2, R-3, S-1
C. P-2, Q-4, R-3, S-1
D. P-1, Q-4, R-3, S-2

Answer

To solve the problem of matching the electronic configurations from List-I with the elements in List-II, we will follow these steps:

### Step-by-Step Solution:

1. **Identify the Atomic Number from Electronic Configuration P (2, 8, 1)**:
- The electronic configuration is 2, 8, 1.
- Calculate the total number of electrons: 2 + 8 + 1 = 11.
- The atomic number is 11, which corresponds to Sodium (Na).
- **Match**: P → 4 (Sodium).

2. **Identify the Atomic Number from Electronic Configuration Q (2, 8, 7)**:
- The electronic configuration is 2, 8, 7.
- Calculate the total number of electrons: 2 + 8 + 7 = 17.
- The atomic number is 17, which corresponds to Chlorine (Cl).
- **Match**: Q → 3 (Chlorine).

3. **Identify the Atomic Number from Electronic Configuration R (2, 8, 6)**:
- The electronic configuration is 2, 8, 6.
- Calculate the total number of electrons: 2 + 8 + 6 = 16.
- The atomic number is 16, which corresponds to Sulphur (S).
- **Match**: R → 2 (Sulphur).

4. **Identify the Atomic Number from Electronic Configuration S (2, 8)**:
- The electronic configuration is 2, 8.
- Calculate the total number of electrons: 2 + 8 = 10.
- The atomic number is 10, which corresponds to Neon (Ne).
- **Match**: S → 1 (Neon).

### Final Matches:
- P → 4 (Sodium)
- Q → 3 (Chlorine)
- R → 2 (Sulphur)
- S → 1 (Neon)

### Summary of Matches:
- P: 2, 8, 1 → Sodium (4)
- Q: 2, 8, 7 → Chlorine (3)
- R: 2, 8, 6 → Sulphur (2)
- S: 2, 8 → Neon (1)