`{:("LIst-I ",,"LIst-II "),("(P) Good conductor of heat and electricity",,"1. NaCl"),("(Q) Soluble in water",,"2.S"),("(R) Poor conductor of electricity",,"3. Cu"),("(S) Yellow flame",,"4. Na"):}`

Options

A. P-3, Q-2, R-4, S-1
B. P-4, Q-2, R-3, S-1
C. P-3, Q-1, R-2, S-4
D. P-1, Q-3, R-2, S-4

Answer

To solve the matching question between List-I and List-II, we will analyze each item in List-I and find the correct corresponding item in List-II.

### Step-by-Step Solution:

1. **Identify the Good Conductor of Heat and Electricity (P)**:
- Among the options, we know that metals are generally good conductors of heat and electricity.
- The best candidate here is **Copper (Cu)**, which is widely used in electrical wiring due to its excellent conductivity.
- Therefore, **P = 3** (P matches with Cu).

2. **Identify the Soluble Substance in Water (Q)**:
- We need to find a substance that is soluble in water.
- **Sodium Chloride (NaCl)** is well-known for being highly soluble in water.
- Thus, **Q = 1** (Q matches with NaCl).

3. **Identify the Poor Conductor of Electricity (R)**:
- Non-metals are typically poor conductors of electricity.
- Among the given options, **Sulfur (S)** is a non-metal and does not conduct electricity well.
- Therefore, **R = 2** (R matches with S).

4. **Identify the Substance that Produces a Yellow Flame (S)**:
- When burned, **Sodium (Na)** produces a characteristic yellow flame.
- Hence, **S = 4** (S matches with Na).

### Summary of Matches:
- P = 3 (Cu)
- Q = 1 (NaCl)
- R = 2 (S)
- S = 4 (Na)

### Final Matching:
- P (Good conductor of heat and electricity) → 3 (Cu)
- Q (Soluble in water) → 1 (NaCl)
- R (Poor conductor of electricity) → 2 (S)
- S (Yellow flame) → 4 (Na)

### Conclusion:
The correct matching is:
- P3, Q1, R2, S4