A metal rod M was dipped in a coloured solution Y. After some time it was observed that the metal rod starts dissolving in the solution and the solution starts fading in colour. However, a coloured precipitate Z was seen at the bottom of the beaker. M, Y and Z could be

Options

A. `M = Zn, " " Y = FeSO_(4), " "Z = Fe`
B. `M = Cu, " " Y = Al_(2)(SO_(4))_(3), " " Z = Al`
C. `M = Ag, " " Y = CuSO_(4), " "Z = Cu`
D. `M = Fe, " " Y = ZnSO_(4), " "Z = Zn`

Answer

A

Explanation

Zn lies above Fe in the reactivity series, hence, it is more reactive than Fe and displaces Fe from `FeSO_(4)` solution.
`underset((M))(Zn_((s)))+underset((Y))(FeSO_(4(aq)))toZnSo_(4(aq))+underset((Z))(Fe_((s)))`