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2.16 of copper metal when treated with n...

2.16 of copper metal when treated with nitric acid followed by ignition of the nitrate gave 2.70 g of copper oxide. In another experiment 1.15 g of copper oxide upon reduction with hydrogen gave 0.92 g of copper. Show that the above data illustrate the Law of Definite Proportions.

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% of Cu in copper oxide in `1^(st)` case
`=(2.16)/(2.70)xx100=80%`
`therefore %` of oxygen = `20%`
% of Cu in copper oxide in `2^(nd)` case `=(0.92)/(1.15)xx100=80%`
% of oxygen = `20%`
The percentage of copper in copper oxide in both the cases is nearly the same. Hence, the given data illustrates the law of definite proportions.
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